Integrand size = 18, antiderivative size = 171 \[ \int f^{a+c x^2} \sin ^2(d+e x) \, dx=\frac {f^a \sqrt {\pi } \text {erfi}\left (\sqrt {c} x \sqrt {\log (f)}\right )}{4 \sqrt {c} \sqrt {\log (f)}}+\frac {e^{-2 i d+\frac {e^2}{c \log (f)}} f^a \sqrt {\pi } \text {erfi}\left (\frac {i e-c x \log (f)}{\sqrt {c} \sqrt {\log (f)}}\right )}{8 \sqrt {c} \sqrt {\log (f)}}-\frac {e^{2 i d+\frac {e^2}{c \log (f)}} f^a \sqrt {\pi } \text {erfi}\left (\frac {i e+c x \log (f)}{\sqrt {c} \sqrt {\log (f)}}\right )}{8 \sqrt {c} \sqrt {\log (f)}} \]
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Time = 0.25 (sec) , antiderivative size = 171, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.222, Rules used = {4560, 2235, 2325, 2266} \[ \int f^{a+c x^2} \sin ^2(d+e x) \, dx=\frac {\sqrt {\pi } f^a e^{\frac {e^2}{c \log (f)}-2 i d} \text {erfi}\left (\frac {-c x \log (f)+i e}{\sqrt {c} \sqrt {\log (f)}}\right )}{8 \sqrt {c} \sqrt {\log (f)}}-\frac {\sqrt {\pi } f^a e^{\frac {e^2}{c \log (f)}+2 i d} \text {erfi}\left (\frac {c x \log (f)+i e}{\sqrt {c} \sqrt {\log (f)}}\right )}{8 \sqrt {c} \sqrt {\log (f)}}+\frac {\sqrt {\pi } f^a \text {erfi}\left (\sqrt {c} x \sqrt {\log (f)}\right )}{4 \sqrt {c} \sqrt {\log (f)}} \]
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Rule 2235
Rule 2266
Rule 2325
Rule 4560
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {1}{2} f^{a+c x^2}-\frac {1}{4} e^{-2 i d-2 i e x} f^{a+c x^2}-\frac {1}{4} e^{2 i d+2 i e x} f^{a+c x^2}\right ) \, dx \\ & = -\left (\frac {1}{4} \int e^{-2 i d-2 i e x} f^{a+c x^2} \, dx\right )-\frac {1}{4} \int e^{2 i d+2 i e x} f^{a+c x^2} \, dx+\frac {1}{2} \int f^{a+c x^2} \, dx \\ & = \frac {f^a \sqrt {\pi } \text {erfi}\left (\sqrt {c} x \sqrt {\log (f)}\right )}{4 \sqrt {c} \sqrt {\log (f)}}-\frac {1}{4} \int e^{-2 i d-2 i e x+a \log (f)+c x^2 \log (f)} \, dx-\frac {1}{4} \int e^{2 i d+2 i e x+a \log (f)+c x^2 \log (f)} \, dx \\ & = \frac {f^a \sqrt {\pi } \text {erfi}\left (\sqrt {c} x \sqrt {\log (f)}\right )}{4 \sqrt {c} \sqrt {\log (f)}}-\frac {1}{4} \left (e^{-2 i d+\frac {e^2}{c \log (f)}} f^a\right ) \int e^{\frac {(-2 i e+2 c x \log (f))^2}{4 c \log (f)}} \, dx-\frac {1}{4} \left (e^{2 i d+\frac {e^2}{c \log (f)}} f^a\right ) \int e^{\frac {(2 i e+2 c x \log (f))^2}{4 c \log (f)}} \, dx \\ & = \frac {f^a \sqrt {\pi } \text {erfi}\left (\sqrt {c} x \sqrt {\log (f)}\right )}{4 \sqrt {c} \sqrt {\log (f)}}+\frac {e^{-2 i d+\frac {e^2}{c \log (f)}} f^a \sqrt {\pi } \text {erfi}\left (\frac {i e-c x \log (f)}{\sqrt {c} \sqrt {\log (f)}}\right )}{8 \sqrt {c} \sqrt {\log (f)}}-\frac {e^{2 i d+\frac {e^2}{c \log (f)}} f^a \sqrt {\pi } \text {erfi}\left (\frac {i e+c x \log (f)}{\sqrt {c} \sqrt {\log (f)}}\right )}{8 \sqrt {c} \sqrt {\log (f)}} \\ \end{align*}
Time = 0.20 (sec) , antiderivative size = 132, normalized size of antiderivative = 0.77 \[ \int f^{a+c x^2} \sin ^2(d+e x) \, dx=\frac {f^a \sqrt {\pi } \left (2 \text {erfi}\left (\sqrt {c} x \sqrt {\log (f)}\right )-e^{\frac {e^2}{c \log (f)}} \left (\text {erfi}\left (\frac {-i e+c x \log (f)}{\sqrt {c} \sqrt {\log (f)}}\right ) (\cos (2 d)-i \sin (2 d))+\text {erfi}\left (\frac {i e+c x \log (f)}{\sqrt {c} \sqrt {\log (f)}}\right ) (\cos (2 d)+i \sin (2 d))\right )\right )}{8 \sqrt {c} \sqrt {\log (f)}} \]
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Time = 0.60 (sec) , antiderivative size = 145, normalized size of antiderivative = 0.85
method | result | size |
risch | \(-\frac {\sqrt {\pi }\, f^{a} {\mathrm e}^{-\frac {2 i d \ln \left (f \right ) c -e^{2}}{\ln \left (f \right ) c}} \operatorname {erf}\left (\sqrt {-c \ln \left (f \right )}\, x +\frac {i e}{\sqrt {-c \ln \left (f \right )}}\right )}{8 \sqrt {-c \ln \left (f \right )}}+\frac {\sqrt {\pi }\, f^{a} {\mathrm e}^{\frac {2 i d \ln \left (f \right ) c +e^{2}}{\ln \left (f \right ) c}} \operatorname {erf}\left (-\sqrt {-c \ln \left (f \right )}\, x +\frac {i e}{\sqrt {-c \ln \left (f \right )}}\right )}{8 \sqrt {-c \ln \left (f \right )}}+\frac {f^{a} \sqrt {\pi }\, \operatorname {erf}\left (\sqrt {-c \ln \left (f \right )}\, x \right )}{4 \sqrt {-c \ln \left (f \right )}}\) | \(145\) |
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Time = 0.27 (sec) , antiderivative size = 161, normalized size of antiderivative = 0.94 \[ \int f^{a+c x^2} \sin ^2(d+e x) \, dx=-\frac {2 \, \sqrt {\pi } \sqrt {-c \log \left (f\right )} f^{a} \operatorname {erf}\left (\sqrt {-c \log \left (f\right )} x\right ) - \sqrt {\pi } \sqrt {-c \log \left (f\right )} \operatorname {erf}\left (\frac {{\left (c x \log \left (f\right ) + i \, e\right )} \sqrt {-c \log \left (f\right )}}{c \log \left (f\right )}\right ) e^{\left (\frac {a c \log \left (f\right )^{2} + 2 i \, c d \log \left (f\right ) + e^{2}}{c \log \left (f\right )}\right )} - \sqrt {\pi } \sqrt {-c \log \left (f\right )} \operatorname {erf}\left (\frac {{\left (c x \log \left (f\right ) - i \, e\right )} \sqrt {-c \log \left (f\right )}}{c \log \left (f\right )}\right ) e^{\left (\frac {a c \log \left (f\right )^{2} - 2 i \, c d \log \left (f\right ) + e^{2}}{c \log \left (f\right )}\right )}}{8 \, c \log \left (f\right )} \]
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\[ \int f^{a+c x^2} \sin ^2(d+e x) \, dx=\int f^{a + c x^{2}} \sin ^{2}{\left (d + e x \right )}\, dx \]
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.24 (sec) , antiderivative size = 236, normalized size of antiderivative = 1.38 \[ \int f^{a+c x^2} \sin ^2(d+e x) \, dx=-\frac {\sqrt {\pi } {\left (f^{a} {\left (\cos \left (2 \, d\right ) - i \, \sin \left (2 \, d\right )\right )} \operatorname {erf}\left (x \overline {\sqrt {-c \log \left (f\right )}} + i \, e \overline {\frac {1}{\sqrt {-c \log \left (f\right )}}}\right ) e^{\left (\frac {e^{2}}{c \log \left (f\right )}\right )} + f^{a} {\left (\cos \left (2 \, d\right ) + i \, \sin \left (2 \, d\right )\right )} \operatorname {erf}\left (x \overline {\sqrt {-c \log \left (f\right )}} - i \, e \overline {\frac {1}{\sqrt {-c \log \left (f\right )}}}\right ) e^{\left (\frac {e^{2}}{c \log \left (f\right )}\right )} - f^{a} {\left (\cos \left (2 \, d\right ) + i \, \sin \left (2 \, d\right )\right )} \operatorname {erf}\left (\frac {c x \log \left (f\right ) + i \, e}{\sqrt {-c \log \left (f\right )}}\right ) e^{\left (\frac {e^{2}}{c \log \left (f\right )}\right )} - f^{a} {\left (\cos \left (2 \, d\right ) - i \, \sin \left (2 \, d\right )\right )} \operatorname {erf}\left (\frac {c x \log \left (f\right ) - i \, e}{\sqrt {-c \log \left (f\right )}}\right ) e^{\left (\frac {e^{2}}{c \log \left (f\right )}\right )} - 2 \, f^{a} \operatorname {erf}\left (x \overline {\sqrt {-c \log \left (f\right )}}\right ) - 2 \, f^{a} \operatorname {erf}\left (\sqrt {-c \log \left (f\right )} x\right )\right )}}{16 \, \sqrt {-c \log \left (f\right )}} \]
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\[ \int f^{a+c x^2} \sin ^2(d+e x) \, dx=\int { f^{c x^{2} + a} \sin \left (e x + d\right )^{2} \,d x } \]
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Timed out. \[ \int f^{a+c x^2} \sin ^2(d+e x) \, dx=\int f^{c\,x^2+a}\,{\sin \left (d+e\,x\right )}^2 \,d x \]
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